Math, asked by reeva06, 9 months ago

the factors of x^2(y-z)+y^2(z-x)+z^2(x-y)​

Answers

Answered by alphymmmmmargert
3

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (((x2)•(y-z))+((y2)•(z-x)))+z2•(x-y)

Step  2  :

Equation at the end of step  2  :

 (((x2)•(y-z))+y2•(z-x))+z2•(x-y)

Step  3  :

Equation at the end of step  3  :

 (x2•(y-z)+y2•(z-x))+z2•(x-y)

Step  4  :

Trying to factor by pulling out :

Factoring:  x2y-x2z-xy2+xz2+y2z-yz2  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  y2z-xy2  

Group 2:  x2y-x2z  

Group 3:  xz2-yz2  

Pull out from each group separately :

Group 1:   (x-z) • (-y2)

Group 2:   (y-z) • (x2)

Group 3:   (x-y) • (z2)

Looking for common sub-expressions :

Group 1:   (x-z) • (-y2)

Group 3:   (x-y) • (z2)

Group 2:   (y-z) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Final result :

 x2y - x2z - xy2 + xz2 + y2z - yz2

here is you are answer

Answered by ryanlobo0907
0

Answer:

Step-by-step explanation:

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