Question

The factors of x²‐239‐972​

Answer 1

Given

$x^{2} -239x-972=0$

Solving, we get,

$x^{2} -239x-972=0$

$\implies x^{2} +4x-243x-972=0$

$\implies x(x+4)-243(x+4)=0$

$\implies (x+4)(x-243)=0$

Now,

$x+4=0\\\implies x = -4$

$x-243=0\\\implies x = 243$

$\boxed{\boxed{\bold{Therefore, \ the \ zeroes \ are \ -4 \ and \ 243}}}}}}}}}}}}$

                                                     

Answer 2

Correct Question

Find the factors of polynomial $\sf{x^{2}-239x-972}$

Answer:-

$\sf{(x-243) \ and \ (x+4) \ are \ the \ factors}$

$\sf{of \ polynomial \ x^{2}-239x-972}$

Given:

The given polynomial is

$\sf{\implies{x^{2}-239x-972}}$

To find:

• Factors of the polynomial.

Solution:

The given polynomial is

$\sf{\implies{x^{2}-239x-972}}$

$\sf{\implies{x^{2}-243x+4x-972}}$

$\sf{\implies{x(x-243)+4(x-242)}}$

$\sf{\implies{(x-243)(x+4)}}$

$\sf\purple{\tt{\therefore{(x-243) \ and \ (x+4) \ are \ the \ factors}}}$

$\purple{\tt{of \ polynomial \ x^{2}-239x-972}}$