The factors of x² -5x+6 are
(x-2)( x-P)
then the value of
P is
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If the HCF of x2+x−12 and 2x2−kx−9 is x−k, find the value of k.
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Let p(x)=x2+x−12 and q(x)=2x2−kx−9
Suppose, h(x)=(x−k) be HCF of p(x) and q(x)
Now, p(x)=x2+x−12
=x2+4x−3x−12
=x(x+4)−3(x+4)
=(x+4)(x−3)
So, either k=−4 or k=3 ...... (i)
Since, (x−k) is HCF
∴q(x)=(x−k)g(x) for some factor g(x) of q(x)
Take x=k
⟹2(k)2−k×k−9=0
⟹2k2−k2−9=0
⟹k2=9⟹k=±3
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