Question

The factors of x²_9 is​

Answer 1

Step-by-step explanation:

Really, it starts with analysis of the expression. With practice and knowledge, notice first that both of the terms are ‘squares’: e.g. x*x = 1st term ( and 3*3 = 9. Notice then, because there is no ‘middle term’ in form of b*x (because the standard quadratic is ‘ax² + bx + c’) that the middle b*x is gone. That occurs because the factors in the binomials used create a ‘zero-pair’ when they are summed. Therefore (x + 3)(x - 3) creates your expression because following the distribution of terms: x*x produces x², then a +3x and a -3x are created, and +3*-3 creates -9, but when the ‘like terms of -3x and +3x are summed it equals 0 and the ‘plain’ x-term is removed during simplification. x² -3x + 3x -9 was produced,