The factors of x²+y²-xy-x are
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Step-by-step explanation:
Is the answer (x-y)(x+y+1)?
You get there by grouping ([x^2-y^2] + 1[x-y]).
x^2-y^2 factors as (x+y)(x-y) so now you have the common factor (x-y) and what's left is (x+y) and +1
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