The factors of x3 -1 + y3 + 3xy are
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1
Answer:
x^2
Step-by-step explanation:
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Answer: x^3-1+y^3+3xy
= x^3+(-1)^3+y^3-3(x)(-1)(y)
= (x-1+y)[x^2+1^2+y^2-(x)(-1)-(-1)(y)-(x)(y)
= (x-1+y)(x^2+1+y^2+x+y-xy)
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