The factors of x3(cube) -1+ y3(cube) + 3xy are
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The solutions for x and y would be in the form of (n,1-n)
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Anonymous:
no ineed factors
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The factorization of the above is:
(x+y-1)(x²-xy+x+y²+y+1)
(x+y-1)(x²-xy+x+y²+y+1)
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