Question

The factors of X6 +8x3+27 is​

Answer 1

Answer:

Question -

• Factorising

${8x}^{3} + 27$

Required Solution -

$= > ( {4x}^{2} - 6x + 9)(2x + 3)$

Using the identity :

${a}^{3} + {b}^{3} = ( {a}^{2} - ab + {b}^{2} )(a + b)$

Now,

${(2x)}^{3} + {3}^{3}$

${(2x)}^{2} - (2x \times 3) + {3}^{2} \: \: (2x + 3)$

$= > ( {4x}^{2} - 6x + 9)(2x + 3)$

Thank You

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