Question

the falcon distance along and angular swimming tanks is 154 m length is 2m more than twice its breadth what is the length and breadth of the summing tanks also find its area
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Answer 1

$\sf{\huge{\red{\star}}}$ Correct Question:-

The falcon distance along rectangular swimming tanks is 154 m. Length is 2m more than its breadth. What is the length and breadth of the swimming tanks also find its area.

${\huge{\red{\star}}}$ Given:-

• Falcon distance along an angular swimming tank (Perimeter of the tanks) = 154 m
• Length is 2m more than twice its breadth.

$\sf{\huge{\red{\star}}}$ To Find:-

• Length and breadth of the tanks
• Area of the tanks.

$\sf{\huge{\red{\star}}}$ Assumption:-

Let the breadth be (x) m

Length = (2x + 2) m

$\sf{\huge{\red{\star}}}$ Solution:-

We know,

$\rm{Perimeter\:of\:rectangle = 2(Length + Breadth)}$

Therefore,

= $\rm{Perimeter\:of\:swimming\:tanks = 2[x+(2x+2)]}$

$\rm{\implies 154 = 2(x+2x+2)}$

$\rm{\implies \dfrac{154}{2} = 3x+2}$

$\rm{\implies 77 = 3x+2}$

$\rm{\implies 77-2 = 3x}$

$\rm{\implies 3x = 75}$

$\rm{\implies x = \dfrac{75}{3}}$

$\rm{\implies x = 25}$

Now,

Calculating the dimensions of the tanks:-

Length of the swimming tanks

= 2x + 2

= $\rm{2\times25+2}$

= $\rm{50+2}$

= $\rm{52\:m}$

Breadth of the swimming tanks = x = 25 m

Therefore,

Length of the swimming tanks = 52 m

Breadth of the swimming tanks = 25 m

Now,

Calculating the area of the tanks:-

We know,

Area of rectangle = (Length×Breadth) sq.units

Therefore,

$\rm{Area\:of\:tanks = 52\times25}$

= $\rm{Area\:of\:tanks = 1300\:m^2}$

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$\sf{\huge{\red{\star}}}$ Formulas Used:-

• Perimeter of rectangle = 2(Length + Breadth) units
• Area of rectangle = (Length×Breadth) sq.units.

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