Question

The far point distance of a short sighted person is 1.5meters. find the focal length, power and
nature of the remedial lens?
(-1.5 m, -0.67D, concave lens)

Answer 1

Answer:

for short sightedness ,,,, focal length =-d here d is far point so focal length is -1.5 m and power = 1/focal length so p= 1/-1.5 ,, p= -0.67D