Question

The far point distance of a short sighted person is 1.5meters. find the focal length, power and

nature of the remedial lens?

(-1.5 m, -0.67D, concave lens)​

Answer 1

Answer:

u = - infinity

v= -1.5 m

1/f=-1/v - 1/u

1/f= -1/1.5 - (-1/ infinity)

1/f= -1/1.5 - 0

1/f= -1/1.5

f=-1.5 m

p=1/f= -1/1.5=-0.67D

nature of lens is concave as it's focal length is negative