Question

the far point of a myopia person is 2.5m in front of the eye. What is the power of the lens required to correct the problem?​

Answer 1

Answer:

The lens should be such that an object at infinity must form its image at the far point. A concave lens of power – 1.25 D is required by the individual to correct his defect.

Explanation:

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Answer 2

Answer:

The power of the lens required to correct the problem is - 2.5 D.

Explanation:

Given Data:

The far point of the Myopic person = 2.5 m

To Find :

The power of the lens is required to correct the problem.

Calculation:​

The defect is Myopia causes problems seeing distant things, hence a concave lens is needed to rectify it and move the far point from 2.5 meters to ∞. Thus, an accurate image of the item at infinity must be created at a distance of 2.5 meters.

u = -∞ and v = -1.5 m

And f = -2.5 m

From the lens formula,

$\frac{1}{v} -\frac{1}{u} =\frac{1}{f}$

Putting all the values, we have

$\frac{1}{v} -\frac{1}{-\infty} =\frac{1}{(-2.5)}$

$\frac{1}{v} +0= -0.4$

Now, taking reciprocal, we have

$v = \frac{1}{(-0.4)} = -2.5 D$

Therefore, the power of the lens required to correct the problem is -2.5 D.

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