Question

The far point of a myopic eye is 150cm.what is the nature and power of lens required to correct the defect?

Answer 1

u = infinity
v = 150
f = ?

1/f = (1/v)-(1/u)
1/f = (1/150)-(1/infinity)
1/f = (1/150) - 0
f = 150 cm
f = 1.5 m

Power = 1/f
= 1/1.5
= 2/3
= 0.66 D