Question

The far point of a myopic person is 60 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

Answer 1

It's Given that Far point of a myopic eye is 75 cm.

=> For a myopic person ,, We know that => Focal length, f = – far point

So ,,

f = - 75 cm

power, P = 1 / f ( m )

Power ( P ) = 100÷ -75 (( after changing 75 cm to m )).

P = - 1.33 D .

Answer