Physics, asked by BiplabArchit, 1 year ago

the far point of a myopic person is 80cm in front of the eye what is the nature and power of the lens required to correct the problem​

Answers

Answered by yashbhatai04
44

defective far point = -80cm = v

far-point of a normal person = -infinity cm = u

acc. to lens formula, 1/f = 1/v - 1/u

1/f = -1/80 + 1/infinity

1/f = -1/80 + 0  (1/infinity = 0)

f = -80cm or -0.8 m

P = 1/f (in m)

P = 1/-0.8

P = -1.25D

Nature= The lens will be concave since its focal length is negative.

Please mark this answer as branliest!

Answered by Anonymous
59

\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}

The nature and the power of lens required to enable him to see very distant objects clearly is concave lens with -1.25 D. Explanation: For person affected with myopic condition, the image instead of forming on retina, it forms in front of it.

Similar questions