Physics, asked by icebot28, 11 months ago

The far point of a myopic person is 90 cm in front of the eye. The power of the lens required to
correct the defect is
dioptres.

Answers

Answered by Viratanmol
1

Answer:

-1.11 D

Explanation:

The nature of the lens used to correct myopic eye is a convex lens.

The power to be used is given by Power of lens, P = 1/f

Far point is 90 cm

u = - infinity and v = -90 cm

Using Lens formula

1/f = 1/v - 1/u

1/f = 1/-90 - 1/-infinity

f = -90 cm

P = 1/f = -1/90*10^-2

= -1.11 D

Power of the lens is -1.11 D

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