Question

The far point of myopic eye is at 50 cm calculate the power of the lens to correct his vision

Answer 1

Answer:

The power of the lens is 2 D.

Explanation:

Given that,

The distance of the image v = -50 cm

In the myopia, The person can not see the far objects but he can see clearly close objects.

The distance of the object u = -25 cm

Using lens formula

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{f}=\dfrac{1}{-50}-\dfrac{1}{-25}$

$\dfrac{1}{f}=\dfrac{1}{50}$

$f=50\ cm$

The power of the lens is

$P= \dfrac{100}{f}$

$P=\dfrac{100}{50}$

$P = 2\ D$

Hence, The power of the lens is 2 D.

Answer 2

Answer:

Answer is -2D

Explanation:

-100/50

2D