Question

The fare of a taxi is ₹ 15 for the first Km and rises by ₹ 10 for each additional Km.

weather this situation involved in Arithmetic Progression? Why?​

Answer 1

Answer:

each km is 15,(15+ 8), (15 + 2 x 8), (15+ 3 x 8), = 15,23, 31, 39,

Hence, the total fare after each km form an AP.

Hope it helps u !!

Mark me as brainliest..

Answer 2

Answer:

taxi fare for first km = ₹15

fare for each additional km = ₹10

required series : 15, 25, 35, 45, 55, ....

a2 - a1 = 25-15 = 10

a3 - a2 = 35-25 = 10

a4 - a3 = 45-35 = 10

therefore, a2 - a2 = a3 - a2 = a4 - a3....

therefore, given situation is in A.P

Step-by-step explanation:

I hope this will help you