Question

the fare of bus ticket from place a to b is rs10. the bus comductor sells 10 ticket during one trip. draw a linear grapgh​

Answer 1

Answer:

Let number of passengers having ticket worth Rs.3 be x

So, total cost of x tickets = 3x

Let number of passengers having ticket worth Rs.10 be y

So, total cost of y tickets = 10y

Since we are given that there are 40 passengers in bus.

So, x+y=40x+y=40 -1

We are also given that the total collection from these passengers is rs.295.

So, 3x+10y= 2953x+10y=295 --2

Substitute the value of x from 1 in 2

So,3(40-y)+10y= 2953(40−y)+10y=295

120-3y+10y= 295120−3y+10y=295

120+7y= 295120+7y=295

7y= 1757y=175

y= 25y=25

Substitute the value of y in 1

x+25=40x+25=40

x=15x=15

So, 15 passengers have tickets worth rs.3

Step-by-step explanation:

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