the farmer moves along the boundary of a square field of side 10m in 40s what will be the magnitude of displacement of the farmer at the end of 2min 20sec
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Answered by
4
Answer:
240 is your answer
Explanation:
the formula for displacement:
vt+1/2 gt
so 10×40×1/2+2×20
400 1/2+2×20
200+2×20
according to bodmas multiplication is 1st
200+40
240
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Answered by
10
distance of one side = 10 m
time taken =40s
therefore, speed = distance /time
= 10/40
=1/4
next
2min in second
=60×2
=120+20
=140second
now,distance=speed×time
=1/4×140
=35meter
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