Question

The farthest is 6 times his son's age 4 years hence the age of the father will be 4 times his son's age find the

Answer 1

Answer:

father's age = 36 years

son's age = 6 years

Step-by-step explanation:

present age of father = x

present age of son = y

father's age is 6 times the age of son

x = 6y. equ (1)

age of father after 4 years = x + 4

age of son after 4 years = y + 4

4 years later father Will be 4 times the age of son

x + 4 = 4(y + 4)

x + 4 = 4y + 16

x - 4y = 16 - 4

x - 4y = 12

substitute x = 6y

6y - 4y = 12

2y = 12

y = 12/2

y = 6

x = 6y

x = 6 × 6

x = 36

therefore the father's age = 36 years

son's age = 6 years

hope you get your answer