Math, asked by narendramodi3648, 1 year ago

The father age 44times of son age at 88 years ago,after 88 years the father age will be 2 times of son age so what is the persent age of son

Answers

Answered by anu522
2
LET FATHER'S AGE [PRESENT] IS - 'X' YR

AND SON'S PRESENT AGE IS 'Y' YRS

THEN ACCORDING TO GIVEN CONDITION-

88 YRS AGO-

AGE OF FATHER- X-88

AGE OF SON-Y-88

THEREFORE EQUATION IS-

X - 88 = 44 [Y-88]

X - 88= 44Y - 3872

X - 44Y = - 3872 + 88

X - 44Y = 3784 ----------------[1]

2ND CONDITION-

88 YRS AFTER-

AGE OF FATHER- X+88

AGE OF SON-Y+88

THEREFORE EQUATION IS-


X+88= 2 [Y+88]

X + 88 = 2Y + 176

X - 2Y = 176 - 88

X -2Y = 88--------------------[2]

BY ELIMINATION METHOD

X - 44Y = 3784
X - 2Y = 88
- + -
____________

- 42 Y = 3696

Y = 88


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