Question

the father age is four time his son age four years hence the age of father will be five times his son age find the present age of father and son in year​

Answer 1

Answer:

FATHER’S AGE= 40+5=45 WHICH IS 3 TIMES THE AGE OF HIS SON

Step-by-step explanation:

LET THE SON’SAGE BE X

THEN FATHR’S AGE WOULD BE= 4X

AFTER 5 YEARS SONS AGE WILL BE 9X+5) AND FATHER’S AGE WOULD BE (4X+5)

IT IS GIVEN THAT THE FATHER WOULD BE 3 TIMES OF THE AGE OF HIS SON

THEREFORE,(4X+5)= 3(X+5)

SIMPLIFYING WE HAVE 4X-3X= 15–5= 10

HENCE SON’S AGE NOW IS 10YRS FATHERE’S AGE IS 4x X=4*10=40

AFTER 5 YRS SON

S AGE WILL BE 10+5=15 YRS

FATHER’S AGE= 40+5=45 WHICH IS 3 TIMES THE AGE OF HIS SON

Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20