Question

The father age is six time than his son's age four years hence the age of father will be four times than his son's age the present age of his son and father
Maths
A pair of two linear equations

Answer 1

Answer:

Step-by-step explanation:

Let son age = x

The age of father six times the age of his son = 6x

Four years hence = 6x +4. Eq 1

The age of father will be four times the age of his son = 4( x+4) Eq 2

Eq 1= Eq 2

6x+4= 4(x+4) = 6x +4 = 4x + 16 = 6x+4-4x-16 =0

2x = 12

x =12/2=6. x=6

Substitute in 6x = 6(6)=36

Hence 6 and 36

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Answer 2

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Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years