Question

the father is 24 years older than his daughter.In 4 years he will be thrice as his daughter.Find their present ages​

Answer 1

Answer:

The daughter is 8 years old.

The father is 32 years old.

Step-by-step explanation:

Let daughter's present age be 'x'.

∴ The Father's age = (x + 24) years

After 4 years,

Daughter's age = (x + 4) years

Father's age = (x + 24 + 4)

                     = (x + 28) years

3(x + 4) = x + 28

3x + 12 = x + 28

3x - x = 28 - 12

2x = 16

∴ x = $\frac{16}{2}$

  x = 8

∴ Father's age = (x + 24)

                         = 8 + 24

                         = 32 years