Question

the father is 45 years older than his son in 15 years the father will be three times as old as his son find their present age​

Answer 1

Answer:

The father is 52.5 years old and son is 7.5 years old.

Step-by-step explanation:

Gívєn -

Father is = 45 years older than his son

15 years later, father will be three times as old as his son

Tσ fínd -

Their present Ages

Sσlutíσn -

✯ Let the ages be -

• Son as x
• Father as (x + 45)

$\rule{300}{1.5}$

✯ 15 years later -

• Son = (x + 15)
• Father = (x + 45) + 15

$\rule{300}{1.5}$

✯ According to the Question -

15 years later, father will be three times as old as his son

$\sf{\implies} \: (x + 45) + 15 = 3(x + 15) \\ \sf{\implies} \: x + 45 + 15 = 3x + 45 \\ \sf{\implies} \: x + 60 = 3x + 45 \\ \sf{\implies} \: 3x - x = 60 - 45 \\ \sf{\implies} \: 2x = 15 \\ \sf{\implies} \: x = \frac{15}{2} \\ \sf{\implies} \: x = 7.5$

Son is presently 7.5 years old

$\rule{300}{1.5}$

✯ Father's present age =

$\sf{\implies} \: (x + 45) \\ \sf{\implies} \: (7.5 + 45) \\ \sf{\implies} \: 52.5$

Father's age = 52.5

$\therefore$ The father is 52.5 years old and son is 7.5 years old.