Question

The father is 48 years old and he has 21 years old son. How many years ago has father 10 times older than his son?

Answer 1

Answer:

Before 18 years age of father was 10 times older than his son.

Step-by-step explanation:

Age of father=48 years

Age of son=21 years

Before x years,

Age of father =48-x

Age of son=21-x

Acc to question,we have to find before how many years father was 10times older than his son....so

Age of father=10(21-x)

48-x=10(21-x)

48-x=210-10x

10x-x=210-48

9x=162

x=162/9

x=18 years

Hope it helps