Math, asked by jitendraaditya86, 11 months ago

the father is 4times older than his son.the son is 36 yrs younger than father.find the present age​

Answers

Answered by muralik2000
0

Answer:

A father is 4 times as old as his son

Let son's age be x years, his father's age is 4x

4x = x + 36

4x - x = 36

3x = 36

x = 36/3

x = 12

The son’s age is 12 years.

The father's age 4x = 4 × 12 = 48 years

Answer the son's age is 12 years and father's age is 48 years

Step-by-step explanation: hope u understood

Answered by Fareedakhan004
0

Answer:

let's sons age be x years,his fathers age is 4x

4x=x+36

3x=36

x=36/3

x=12

the sons age is 12 years

the fathers age 4x=4×12=48 years

therefore the son age is 12 years and father age is 48 years

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