Question

the father is 7 times as old as his son 2 years ago the father was 13 times as old as his son's how old are they now

Answer 1

Let the age of son be x.

Then the age of the father is 7 times as old as his son = 7x.

Given that 2 years ago the father was 13 times as old as his son.

7x - 2 = 13(x - 2)

7x - 2 = 13x - 26

7x - 13x = -26+ 2

-6x = -24

x = 4.

If the age of son = 4 years, then the age of his father will be 7* 4 = 28 years.

Therefore the age of son = 4 years.

                  the age of father = 28 years.


Hope this helps!