Question

The father is 7 times older than his son.After 5yr the sum of their ages would be 50yr.The son's age at present is

Answer 1

Heya !!!


Let present age of son be X years.


Present age of father = 7X years.



After five years age of son = ( X + 5 ) years


After five years age of father = ( 7X + 5 ) years.


According to question,


( X + 5 ) + ( 7X + 5 ) = 50


8X + 10 = 50


8X = 50-10


X = 40/8 = 5 years


Present age of son = X = 5 years

And,

Present age of father = 7X = 7 × 5 = 35 years.



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Answer 2

X and 7x
x+5 and 7×+5=50
$x + 5 + 7x + 5 = 50 \\ 8x + 10 = 50 \\ 8x = 40 \\ x = 5$
His present age is 5 yrs