The father is nine times the age of his son. After three years, the father’s age will be five times the age of his son. Find their present ages.
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Answer:
Let the sons age=xyrs
fathers=9x
afters 3 yrs Son=x+3yrs
father 9x+3yrs
the eqn is 5(x+3) = 9x+3
5x+15=9x +3
15-3=9x-5x
12 = 4x
x = 3
Sons Present age=3yrs
fathers presentage = 9x=27 yrs
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