Math, asked by shirinburhan424, 11 months ago

the father is three times old as his son after 15 years he will be twice as old as his son what are their present ages

Answers

Answered by aaliyas205
1

Answer:

age of son be x

age of father = 3x

after 15 years

2 ( x + 15 ) = 3x + 15

2x + 30 = 3x + 15

30 - 15 = 3x - 2x

x = 15years ( son age)

father age = 3 × x

= 3 × 15

= 45years

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