Question

The father of a girl is three years older then his mother six years ago the average age of the girl and her parents was 32 years and the age of the father is twice the present age of his daughter what is the present age of the mother.​

Answer 1

Answer:

Let the daughter's age be x years. Then,

Mother's age =3x years and  

Father's age=(3x+5) years

When daughter's age is 10 years,

Father's age =(3×10+5)=35 years.

When daughter was born,

Father's age=(35−10)=25 years.

Step-by-step explanation:

Answer 2

Answer:

61 is the age of her mother

Step-by-step explanation:

first of all do 32+32= 64 now this is the age of his father as written on the top her mother is 3 years smaller than her father so 64-3=61.

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