Math, asked by abhishek817428, 1 month ago

The father's age is 3 times the age of his son. 6 years ago, the father's age was 5 times the age of his son. Find his present age. please explain ​

Answers

Answered by cutiepie7610
1

Answer:

Let the present age of son be x

And that of father be y

According to the question

3x=y ----(1)

Also

5 years ago

y-5=5(x-5) ----(2)

Substitute the value of y from (1) in (2)

3x-5=5x-25

25-5=5x-3x

2x=20

x=10

y=3x

y=30

Present age of son is 10 years and that of father is 30 years

Step-by-step explanation:

Hope so the answer helps

Answered by hiteshreemaniar
1

Answer:

10 years

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