Question

the father's age is 5/2 times his daughter's age. eight years ago, the age of the father was four times daughter's age. the present age of the daugter is

A. 6 yrs
B. 16yrs
C. 10yrs
D. 9yrs

Answer 1

Answer:

16 year

Step-by-step explanation:

Let the present age of daughter be 'x' year. So, the age of father should be (5/2) times of x = 5x/2

Eight year ago:

Age of daughter = present - 8 = x - 8

Age of father = 5x/2 - 8 = (5x - 16)/2

At that time, father was four times daughter's age.

=> father's age = 4 × daugther's age

=> (5x - 16)/2 = 4(x - 8)

=> 5x - 16 = 8(x - 8)

=> 5x - 16 = 8x - 64

=> 64 - 16 = 8x - 5x

=> 48 = 3x

=> 16 = x

Hence, the present age of daugther is 16 year

Answer 2

Given :-

The father's age is 5/2 times his daughter's age. eight years ago, the age of the father was four times daughter's age

To Find :-

Age of daughter

Solution :-

Let the age of daughter be a. Father age = 5/2a

Eight years ago

Age of daughter = a - 8

Age of father = 5a/2 - 8

Now

5a/2 - 8 = 4(a - 8)

5a - 16/2 = 4a - 32

5a - 16 = 2(4a - 32)

5a - 16 = 8a - 64

5a - 8a = 16 - 64

-3a = -48

a = -48/-3

a = 48/3

a = 16 years

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