Question

the father's age is 6 times his son's age. Four year hence ,the age of the father will be four times his son's age. Find their present ages

Answer 1

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The father's age is six times his son's age . Four years hence the age of father will be four times his son's age , The present age in years of the son and the father are respectively


( A ) 5 and 30 
( B ) 3 and 24 
( C ) 6 and 36 
( D ) 4 and 24

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asked Aug 27, 2015 by pady_1



1 Answer

(C) 6 and 36 

Let son age = x 

The age of father six times the age of his son = 6x 

Four years hence = 6x +4.     Eq 1

The age of father will be four times the age of his son = 4( x+4)      Eq 2

Eq 1= Eq 2

6x+4= 4(x+4) = 6x +4 = 4x + 16          = 6x+4-4x-16 =0 

2x = 12

x =12/2=6.   x=6

Substitute in 6x = 6(6)=36

Hence 6 and 36

Answer 2

let the son age be =x
then father age is =6x
hence four year
sons age =x+4
father age =4(x+4)
when u you solve the equ.
x=6x and 
x+4=4(x+4)
then age of sun is 6
the present age of 
son= 10
father= 40
hope it help u
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