Question

The father's age is six times his ony age. six years here the age
of father will be four times his son's age. Find the
present age. (in years)
of the son and father ​

Answer 1

Answer:

hope it will help you

Step-by-step explanation:

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

Answer 2

Correct Question :

The father's age is six times his son's age . Six years hence the age of the father will be four times his son's age . Find the present age of the son and father ( in years ) .

Solution :

Let the present age of son be  x

So , Father's present age = 6x

Six years hence the age of the father will be four times his son's age .

⇒ ( 6x + 6 ) = 4 ( x + 6 )

⇒ 6x + 6 = 4x + 24

⇒ 6x - 4x = 24 - 6

⇒ 2x = 18

⇒ x = 9  $\orange{\bigstar}$

Present age of son ,

x = 9 years  $\pink{\bigstar}$

Present age of father ,

6x = 6(9)= 54 years  $\green{\bigstar}$