Math, asked by scshuklaknp, 10 months ago

The father's age is six times his son's age. four years hence, the age of the father will be four times his son .the present ages in years of the son and father are

Answers

Answered by shivamkumar8914
8

Answer:

Let the son's present age be 'x' years. So, his father's present age will be 6x.

Four years hence, father's age will be 6x+4

6x+4=4(x+4)

6x+4=4x+16

6x-4x=16-4

2x=12

x=12/2

x=6

Therefore, son's present age is 6 years and his father's present age is 6x=6 × 6=36

Therefore, father's age is 36 years.

Answered by prathamesh2580
8

Answer:

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