Question

The father's age is six times his son's age. four years hence, the age of the father will be four times his son .the present ages in years of the son and father are​

Answer 1

Answer:

Let father's age be x and son's age be y

Thus,

x = 6y --------------(1)

Now after 4 years,

Father's age = x + 4

Son's age = y+4

Thus after 4 years,

x + 4 = 4(y + 4)

x + 4 = 4y + 16

From equation(1) -----> x = 6y

6y + 4 = 4y + 16

2y = 12

y = 6

Thus son's present age is 6 years

x = 6y

x = 6(6) = 36

Thus Father's present age is 36 years

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

Assumption,

Father's present age = p years

Also,

Son's present age = t years

So,

Situation,

p = 6t ................…(1)

Four years later,

(p + 4) = 4(t + 4)

p - 4t = 12 …..............(2)

Now,

Substitute the value of p from (1) in (2),

p - 4t = 12

6t - 4t = 12

2t = 12

t = 12/2

t = 6

Substitute the value of t in (1),

p = 6t

p = 6 × 6

p = 36

Therefore,

Present age of father = 36 years

Present age of son = 6 years