Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively

(A) 4 and 24                                       

(B) 5 and 30

(C) 6 and 36                                       

(D) 3 and 24​

Answer 1

Answer: (C)

Explanation: Let the age of father be x and of son is y.

Then according to question,

x = 6y …..(i)

Four years hence age of son will be y + 4 and age of father will be x + 4

Then according to question,

x + 4 = 4 (y + 4)

x – 4y = 12 …..(ii)

Solving equations (i) and (ii) we get:

y = 6 and x = 36

Answer 2

Answer:

C is correct

Step-by-step explanation:

The present ages (in year) of the son and the father are, respectively

.SOLUTION: Let x yr be the present age of father and

y yr be the present age of son.

Hence, present age of father is 36 yr and age of son is 6 yr.

Let ages of father and son be 6x years and x years respectively.

So, 6x + 4 = 4(x+4)

or, 6x + 4 = 4x + 16

or, 2x = 12

or, x = 6

So, 6x = 6*6 = 36

Answer:- (C) - 6 and 36

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Additional information ❤

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

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SIMILAR QUESTIONS ❤

Four years ago age of a person was 4 times that of his son. six years later the age of the person will be 10 years less than thrice the age of his son. Find the present ages of the person and his son

( A ) x=44 and y=14

( B ) x=54 and y=24

( C ) x=34 and y=14

( D ) x=44 and y=24

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Hope it helps

:)