Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively

(A) 4 and 24                                       

(B) 5 and 30

(C) 6 and 36                                       

(D) 3 and 24​

Answer 1

Answer:

(C) 6 and 36                                      

Step-by-step explanation:

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

Answer 2

Let ages of father and son be 6x years and x years respectively.

So, 6x + 4 = 4(x+4)

or, 6x + 4 = 4x + 16

or, 2x = 12

or, x = 6

So, 6x = 6*6 = 36

Answer:- (C) =  6 and 36