Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively

(A) 4 and 24                                       

(B) 5 and 30

(C) 6 and 36                                       

(D) 3 and 24​

Answer 1

Answer: (C)

Explanation: Let the age of father be x and of son is y.

Then according to question,

x = 6y …..(i)

Four years hence age of son will be y + 4 and age of father will be x + 4

Then according to question,

x + 4 = 4 (y + 4)

x – 4y = 12 …..(ii)

Solving equations (i) and (ii) we get:

y = 6 and x = 36

Answer 2

Answer:

(C) 6 and 36  

Step-by-step explanation:

Given,

• father’s age is six times his son’s age
• four years hence, the age of the father will be four times his son’s age

Let the father's age be x and the son's age be y

The required Equations are:

• x = 6y ⇒ 1
• (x + 4) = 4(y + 4) ⇒ 2

Solving the equations:

Substitute equation 1 in 2

     (x + 4) = 4(y + 4)

     6y + 4 = 4y + 16

     6y - 4y = 16 - 4

     2y = 12

    y = 6 ⇒ 3

Substitute equation 3 in 1

     x = 6y

     x = 6(6)

     x = 36