Math, asked by αηυяαg, 2 months ago

The father's age is six times his son's age Four years hence, the age of the fat
four times his son's age The present ages of the son and the father are, respectiv​

Answers

Answered by VenomBIast
42

\large{\underline{\underline{\tt{\red{Answer~ -}}}}}

Given that,

Age of father is six times age of his son. Four years hence or after four years, The age of father will be four times his son's age.

❍ So, Let's consider age of his son be x years.

⠀ ⠀Therefore, age of father will be 6x years.

⠀━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

☆ After four years,

Age of Son = (x + 4) years

Age of father = (6x + 4) years

⠀⠀⠀

\begin{gathered}\qquad\bigstar\:{\underline{\pmb{\sf{\red{According~to~the~Question~:}}}}}\\\\\\ \qquad\dashrightarrow\sf Father's\:age = 4 \bigg(Son's\:age \bigg)\\\\\\ \qquad\dashrightarrow\sf 6x + 4 = 4 \bigg(x + 4 \bigg)\\\\\\ \qquad\dashrightarrow\sf 6x + 4 = 4x + 16\\\\\\ \qquad\dashrightarrow\sf 6x - 4x = 16 - 4\\\\\\ \qquad\dashrightarrow\sf 2x = 12\\\\\\ \qquad\dashrightarrow\sf x = \cancel{\dfrac{12}{2}}\\\\\\ \qquad\dashrightarrow{\underline{\boxed{\pmb{\frak{x = 6}}}}}\:\bigstar\\\\\end{gathered}

Therefore,⠀⠀

Age of Son, x = 6 years

Age of his father = 36 years

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\:Present\:Age\:of\:father\:\&\:his\:son\:is\:{\pmb{36\:\sf{and}\:6\:years}}\:\sf{respectively.}}}}

Answered by mehakShrgll
5

hope the above attachment helps u

Attachments:
Similar questions