Question

The father's age is six times his son's age. Six years hence the age o
will be four times his son's age. Find the present ages (in years) of the son and father.​

Answer 1

Answer: Acc. to me,

Son's age= 9 yrs

Father' age = 54 yrs

Step-by-step explanation:

Let son's present age be x

Therefore, father's age = 6x

After 6 years,

Son's age = x + 6

Father's age = 6x+6. (Eq. 1)

Also, father's age will be 4 times his son's age after 6 yrs so,

Father's age = 4(x+6). (Eq. 2)

Equating eq. 1 and 2 we get,

6x + 6 = 4x + 24

2x = 18

x = 9

Therefore, son's present age = 9 yrs

And father's present age = 6 × 9

= 54 yrs

Answer 2

Answer:

6 and 36 yrs

Step-by-step explanation:

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y  

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years