the father's age is three times the sum of ages of his two children . after 5 years his age will be twice the su of ages of his two children . find the age of father.
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Let the present age of father be ‘a’ and present sum of age of sons be 'b'.
Given,
Father’s age is three times the sum of ages of his two children.
After 5 years
His age will be twice the sum of ages of two children.
⇒ a = 3b
Also, a + 5 = 2(b + 10) (10 is added because of two sons)
⇒ 3b + 5 = 2b + 20
⇒ b = 15
Thus, a = 3b = 45
Hence,
Age of father =>> 45 years!
Let the present age of father be ‘a’ and present sum of age of sons be 'b'.
Given,
Father’s age is three times the sum of ages of his two children.
After 5 years
His age will be twice the sum of ages of two children.
⇒ a = 3b
Also, a + 5 = 2(b + 10) (10 is added because of two sons)
⇒ 3b + 5 = 2b + 20
⇒ b = 15
Thus, a = 3b = 45
Hence,
Age of father =>> 45 years!
10122003:
thank u brainliest
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