Question

the fathers age is six times his sons age. four years after, the fathers age will be four times his sons age. find present age of father and his son.

Answer 1

Let present age,

son's age = x

father's age = 6x

Four years after,

son's age = x+4

father's age = 6x+4

6x+4 = 4(x+4)

6x+4 = 4x+16

6x-4x = 16-4

2x = 12

x = 12/2

x = 6

Present age of son = x = 6 years

Present age of father = 6x = 6×6 = 36 years

IF IT WILL BE HELPFUL , THEN MARK IT AS BRAINLIEST

Answer 2

Answer:

let the present age of son be x

let father's age be y

a/q

y=6x. ....(I)

four years later

age of son = x+4

age of father =y+4

again a/q

y+4=4(x+4)

6x+4=4x+16

2x=12

x=6

therefore age of son = 6 years

and age of father = 6×6=36 years

Step-by-step explanation:

thanks..