Question

the fathers age is three times the sum of the ages of his two children after five years his age will be two times the sum of there ages. find the present age of father?​

Answer 1

Step-by-step explanation:

Let the age of father =x years

The sum of the age of 2 children =y years

According to the first condition

⇒x=3y.....eq1

After 5 years

⇒ Father's age =x+5

⇒ The sum of ages of his two children =y+10

According to the second condition

⇒x+5=2(y+10)⇒x+5=2y+20

⇒x−2y=15....eq2

Put the value of x from eq1

⇒3y−2y=15⇒y=15

Put y=15 in eq1

⇒x=3×15⇒x=45

Hence, father age =45 years

Answer 2

$\text{ \large \underline{ \red{Question:-}}}$

the fathers age is three times the sum of the ages of his two children after five years his age will be two times the sum of there ages. find the present age of father?

Step-by-step explanation:

$\text{ \large \underline{ \blue{Answer:-}}}$

➯Let the age of the 2 children be x and y.

➣Given that

➯Father’s age is three times the age of his two sons.

➣Then,

➯present age of father is 3(x+y)

➣Now,

➯it is also given, after 5 years, his age will be twice the sum of the ages of his son.

➣Therfore,

➯after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

➾3(x+y)+5 = 2(x+5+y+5)

➾3x+3y+5 = 2x+10+2y+10

➾3x+3y+5 = 2x+2y+20

➾3x-2x+3y-2y = 20–5

➾x+y = 15

➣Now

➯the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

➣Thus

➯the age of the father is 45.

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