Question

The feet of two vertical posts are 50m apart.the posts are 6m and 10m high .what is the length of cable required to join the tops of the posts

Answer 1

Answer:

Step-by-step explanation:

Please refer the attachment to see the figure of this problem.

In the figure, PQ = pole with height of 10 m

                     RS = Pole with height of 6 m

                      T and S are point at same horizontal level

PQ = PT + TQ

⇒ PT = 10 - 6 = 4 m              ( QT = RS = 6 m)

In ΔPTS,

tan ∠ PST = perpendicular/base

                = PT/TS

                = 4/50

⇒ ∠ PST = 4.57°

Now, cos ∠PST = base/hypotenuse

        cos 4.57° = TS/PS

          0.99 = 50/PS

⇒    PS = 50/0.99 = 50.5 m

Hence, length of cable required to connect the top of the poles = 50.5 m