the fermi energy of silver is 5.5eV . Find the fermi velocity in conduction electrons in silver.
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Answer:
Explanation:
The Fermi energy of silver, EF = 5.5 eV = 5.5 × 1.602 × 10–19 J
The relaxation time of electrons in silver, τ = 3.97 × 10–14 S
Fermi velocity, VF = ?
Mean free path, λ = ?
We know that images
or images
1.39 × 106 m/s
The mean free path, λ = VFτ
= 1.39 × 106 × 3.97 × 10−14
= 5.52 × 10−8 m
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