The fermi energy of sodium is 3eV. Calculate the difference in energy between the neighboring levels at the highest energy state in a cubical box of side 1 cm.
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Explanation:
(a) The conduction electrons per cubic meter in zinc:
n=(65.37g/mol)/(6.02×1023mol)2(7.133g/cm3)=1.31×1023cm−3=1.31×1029m−3
(b) EF=me0.121h2n2/3=(9.11×10−31kg)(1.60×10−19J/eV)0.121(6.63×10−34J.s)2(1.31×1029m−3)2/3=9.43eV
(c) Equating the Fermi energy to21mevF2we find
vF=mec22EFc2
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